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If a, b, c are all non-zero and a+b+c=0, then (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)= ?.

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Solution :We have, a,B,C are all non-zero and a+b+c=0, THEREFORE
`a^(3)+b^(3)+c^(3)=3abc`
Now, `(a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)=(a^(3)+b^(3)+c^(3))/(ABC)=(3abc)/(abc)=3`


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