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If `a, b, c` are in AP or GP or HP, then `(a-b)/(b-c)` is equal to

Answer» For a, b, c to be in GP, we must have
`b/a=c/b=r` or `b/a=c/b=1/r`.
Case I When `b/a=c/b=r`.
In this case, `b=ar` and `c=br`.
`:. (a-b)/(b-c)=(a-ar)/(b-br)=(a(1-r))/(b(1-r))=a/b`
Case II When `b/a=c/b=1/r`.
In this case, `a=br` and `b=cr`
`:. (a-b)/(b-c)=(br-b)/(cr-c)=(b(r-1))/(c(r-1))=b/c`.
Hence, the value of `((a-b)/(b-c))` is `a/b` or `b/c`.


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