InterviewSolution
Saved Bookmarks
| 1. |
If `a, b, c` are in AP or GP or HP, then `(a-b)/(b-c)` is equal to |
|
Answer» For a, b, c to be in GP, we must have `b/a=c/b=r` or `b/a=c/b=1/r`. Case I When `b/a=c/b=r`. In this case, `b=ar` and `c=br`. `:. (a-b)/(b-c)=(a-ar)/(b-br)=(a(1-r))/(b(1-r))=a/b` Case II When `b/a=c/b=1/r`. In this case, `a=br` and `b=cr` `:. (a-b)/(b-c)=(br-b)/(cr-c)=(b(r-1))/(c(r-1))=b/c`. Hence, the value of `((a-b)/(b-c))` is `a/b` or `b/c`. |
|