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If `(a-b), (b-c),(c-a)`are in G.P. then prove that `(a+b+c)^2=3(a b+b c+c a)` |
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Answer» `((b-c))/((a-b))=((c-a))/((b-c)) rArr (b-c)^(2)=(a-b)(c-a)` `rArr b^(2)+c^(2)-2bc=ac-a^(2)-bc+ab` `rArra^(2)+b^(2)+c^(2)=ab+bc+ac` `rArr (a+b+c)^(2)=3(ab+bc+ac)" "["adding "2(ab+bc+ac)" on both sides"]`. |
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