1.

If a, b, c are positive real numbers, then `a^("log"b-"log"c) xx b^("log"c-"log"a) xx c^("log"a - "log"b)`

Answer» Correct Answer - B
We have,
`"log" {a^("log"b-"log"c) xx b^("log"c - "log" a) xx c^("log"a-"log"b)}`
`= ("log" b-"log"c)"log" a + ("log"c-"log"a)"log"b + ("log"a-"log"b)"log"c `
= 0
`a^("log"b-"log"c) xx b^("log"c - "log" a) xx c^("log"a-"log"b)=1`


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