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If `a,b,c inR` then prove that `sec^2theta=(bc+ca+ab)/(a^2+b^2+c^2)`only if a = b = c. |
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Answer» We know that `sec^2thetage1` `:. (bc+ca+ab)/(a^2+b^2+c^2)ge 1` `rArr bc+ca+abgea^2+b^2+c^2` `rArra^2+b^2+c^2-ab-bc-cale0` `rArr(a-b)^2+(b-c)^2+(c-a)^2le0` `rArra-b=0,b-c=0" and "c-a=0` `rArra=b=c` |
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