1.

If (a+b)/(xa+yb) = (b+c)/(xy+yc) = (c+a)/(xc+ya)" where " x + y ne 0 anda + b + c ne 0, then each of these ratios is equal to

Answer»

1
`1/(x+y)`
` 2/(x+y)`
` 2 /(a+b)`

Solution :(i) Bach RATIO = `("Sum of all antecedents")/("Sum of all the consequents")`.
(II) Bach fraction is equal to the ratio of sum of the numerators and the sum of the DENOMINATORS of all the equivalent fractions.


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