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If `A`is a square matrix, using mathematical induction prove that `(A^T)^n=(A^n)^T`for all `n in Ndot`

Answer» We will prove it using mathematical induction.
For, `n = 1`,
`L.H.S = (A^T)^1 = A^T`
`R.H.S. = (A^1)^T = A^T`
As, `L.H.S.= R.H.S`, our equation is true for `n = 1`.
Let, our equation is true for `n = k` where `k` is a natural number.
Then, `(A^T)^k = (A^K)^T->(1)`.
Now, we have to prove, for `n = k+1`, given equation is true.
For, `n = k+1`,
`L.H.S. = (A^T)^k+1`
`=(A^T)^k*(A^T)^1`
From (1),
`=(A^k)^T*A^T`
`=(A^k*A)^T`
`=(A^(k+1))^T`
`R.H.S = (A^(k+1))^T`.
`:. L.H.S. = R.H.S.`, for `n = k+1`.
Thus, our equation is true for `n = k+1`.
`:. (A^T)^n = (A^n)^T`.


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