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    				| 1. | Find the value of `lambda,`a non-zero scalar, if `lambda[1 0 2 3 4 5]+2[1 2 3-1-3 2]=[4 4 10 4 2 14]` | 
| Answer» `lambda[[1,0,2],[3,4,5]] +2[[1,2,3],[-1,-3,2]] = [[4,4,10],[4,2,14]]` So, `lambda+2 = 4 => lambda = 2` `2lambda+6 = 10=> lambda = 2` `3lambda - 2 = 4=> lambda = 2` `4lambda - 6 = 2=>lambda = 2` `5lambda +2 = 12=> lambda = 2` So, solving all the equations, we get the same solution i.e. `lambda = 2`. | |