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If `a = "log"2, b = "log" 3, c ="log" 7 " and " 6^(x) = 7^(x+4)` then x=A. `(4b)/(c+a-b)`B. `(4c)/(a+b-c)`C. `(4b)/(c-a-b)`D. `(4a)/(a+b-c)` |
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Answer» Correct Answer - B We have, `6^(x) = 7^(x+4)` `rArr x "log" 6 = (x+4)"log" 7` `rArr x = (4"log"7)/("log"6-"log"7) = (4"log"7)/("log"2 + "log"3-"log"7) = (4c)/(a+b-c)` |
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