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If a = log2412, b = log3624, c = log4836, then prove that 1 + abc = 2bc. |
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Answer» 1 + abc = 1 + log2412. log3624. log4836 = 1 + log3612. log4836 = 1 + log4812 = log4848 + log4812 [∵ logax. logba = logbx] = log48 (48 × 12) = log48 (24 × 24) = log48 (24)2 = 2 log4824. ...(i) Also, 2bc = 2 log3624. log4836 = 2 log4824 ...(ii) From (i) and (ii), we have RHS = LHS. |
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