1.

If `a_(n) gt a_(n-1) gt …. gt a_(2) gt a_(1) gt 1`, then the value of `"log"_(a_(1))"log"_(a_(2)) "log"_(a_(3))…."log"_(a_(n))` is equal to

Answer» Correct Answer - B
We have,
`"log"_(a_(1)) "log"_(a_(2)) "log"_(a_(3))…. "log"_(a_(n-1)) "log"_(a_(n)) a_(n)^(a_(n-1)^(" "a_(n-2)^(" ".^(.^(.^(a_(1)))))))`
` = "log"_(a_(1)) "log"_(a_(2)) "log"_(a_(3))…. "log"_(a_(n-1)) a_(n-1)^(" "a_(n-2)^(" ".^(.^(.^(a_(1))))))`
`= "log"_(a_(1))"log"_(a_(2))"log"_(a_(3))..... "log"_(a_(n-2)) a_(n-2)^(" "a_(n-3)^(" ".^(.^(.^(a_(1))))))`
`=...= "log"_(a_(1)) a_(1) =1`


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