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If `alpha, beta` are different values of `theta` satisfying the equation `5 cos theta-12 sin theta=11`. If the value of `sin (alpha + beta) =-(5k)/(169)` , then find the value of k. |
Answer» given that, `5cos theta - 12sintheta= 11` `(5/13)sin theta - (12/13)sin theta = 11/13` `sin (phi- theta) = 11/13` let `sin x = sin a` we can say that `x=a or pi - a` `phi- theta = alpha- phi or pi-(alpha- phi) ` `pi - (alpha- theta) = (beta- phi)` `pi- alpha+ phi= beta - phi` `pi+ phi + phi = alpha + beta` `sin(pi + 2phi) = sin(alpha+ beta)` `sin (alpha+beta) = - sin 2 phi = -2sinphicos phi` `= -2*5/13* 12/13` `sin (alpha+ beta)= -120/169` `(-5k)/cancel(169) = -120/cancel(169)` we get, `:. k = 24` |
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