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If an electron in H atom has energy of `-76.4` kcal `"mol"^(-1)` .The orbit in which the electron is present isA. IstB. 2ndC. 3rdD. 4th |
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Answer» `E_(n) = (-313.6)/(n^(2)) kcal mol^(-1)` `rArr -78.4 = (-313.6)/(n^(2))` `:. N= 2` |
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