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If an electron is moving around a nucleus of charge `3theta`in a circular orbit of radius `10^(-10)`m,then calculate the initial frequency of light emitted by the electron.A. `4.2times10^(15)Hz`B. `0.36times10^(15)Hz`C. `3.6times10^(15)Hz`D. `4.2times10^(15)Hz` |
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Answer» Correct Answer - C We know that, `(mv^(2))/r=(2theta^(2))/(5pivarepsilon_(0)r^(2))or v=((2theta^(2))/(4pivarepsilon_(0)mr))^(1//2)` Also,frequency=f=`v/(2pir)= ((2theta^(2))/(4pivarepsilon_(0)mr))^(1//2)times1/2pir` therefore`f=((1.414)(9times10^(9))^(1//2)times1.6times10^(-19))/((9.1times10^(-31))^(1//2)times2pi(10^(-10))^(3//2))` cong`3.6times10^(15)Hz` |
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