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If `angleA` and `angleP` are acute angle such that `tanA=tanP`, then show that `angleA=angleP`. |
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Answer» Let we create a right angle triangle `ABP` with the given details. Please refer to video to see the triangle. Then, `tanA = (BP)/(AB)` `tanP = (AB)/(BP)` It is given, `tanA = tanP` `:. (BP)/(AB) = (AB)/(BP)` `=>BP^2 = AB^2` `=>BP = AB` We know, opposite angles of equal sides are also equal. `:. /_A = /_P` |
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