1.

If A, B and C are interior angles of a triangle ABC, then show that `sin((B+C)/2)=cosA/2`.

Answer» In `deltaABC`
`A+B+C=180^(@)`
`rArrB+C=180^(@)-A`
`rArr(B+C)/(2)=90^(@)-(A)/(2)`
`rArr"sin" (B+C)/(2)=sin(90^(@)-(A)/(2))`
`rArr"sin"(B+C)/(2)="cos"(A)/(2)`


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