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Express `cot 85^o +cos75^o`in terms of trigonometric ratios of angles between `0^o`and `45^o` |
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Answer» Here, we will use `cotx = tan(90-x)` `cosx = sin(90-x)` Now, our expression is, `cot85^@+cos75^@ = tan(90^@-85^@)+sin(90^@-75^@)` `tan5^@+sin15^@` |
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