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If `bgta,` then `int_(a)^(b)(dx)/(sqrt((x-a)(b-x)))` is equal toA. `(pi)/(2)`B. `pi`C. `(pi)/(2)(b-a)`D. `(pi)/(4)(b-a)` |
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Answer» Correct Answer - B `int _(a)^(b) (dx)/(sqrt(x-a)(b-x))=int_(a)^(b) 1/(sqrt(-x^(2) + (a+b) x - ab))dx` , ` = int _(a)^(b) 1/(sqrt(((b-a)/2)^(2) - (x-(a+b)/2)^(2)))dx = [ sin^(-1).(((x-(a+b))/2)/((b-2)/2))]_(a)^(b)` ` = sin^(-1) 1- sin^(-1) (-1)` ` = pi/2 + pi/2 = pi` |
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