1.

If cos A = (5)/(13) and A " is not in first quardrant, then find the value of " (sinA-cosA)/(tanA+1).

Answer»

Solution :GIVEN that `cosA=(5)/(13)and A " is not in first quardrant" `
`RARR A " is in fourth quardrant"`.
`SIN A =(-12)/(13)and tanA=(-12)/(13)`
Now, `(sinA-cosA)/(tanA+1)=((-12)/(5)-(5)/(13))/((-12)/(5)+1)=(-17)/(13)xx(-5)/(7)=(85)/(91)`.


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