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If cos A = (5)/(13) and A " is not in first quardrant, then find the value of " (sinA-cosA)/(tanA+1). |
Answer» Solution :GIVEN that `cosA=(5)/(13)and A " is not in first quardrant" ` `RARR A " is in fourth quardrant"`. `SIN A =(-12)/(13)and tanA=(-12)/(13)` Now, `(sinA-cosA)/(tanA+1)=((-12)/(5)-(5)/(13))/((-12)/(5)+1)=(-17)/(13)xx(-5)/(7)=(85)/(91)`. ![]() |
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