If `cosx = -sqrt15/4` and `pi/2 < x < pi`, find the value of `sinx` – InterviewSolution

InterviewSolution

1.	If `cosx = -sqrt15/4` and `pi/2 < x < pi`, find the value of `sinx`
Answer» `sin^x+cos^2x=1` `sin^2x=1-cos^2x` `=1-(sqrt15/4)^2` `=1-15/16=1/16` `sinx=pm1/4` `sinx=1/4`.

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