1.

If earth has a mass 9 times and radius 4 times than that of a planet 'P'. Calculate the escape velocity at the planet 'P' if its value on earth is 11.2 kms^(-1).

Answer»

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Solution :`v_e= SQRT((2GM)/(R_e)), v_(p)= (sqrt(2GM_p))/(R_p)`
`M_p= (M)/(9), R_p = (R_e)/(4)`
`:. ""v_p= sqrt(2G(M)/(9)XX(4)/(R_e))`
`=(2)/(3)sqrt((2GM)/(R_e))=(2)/(3)xx11.2= (22.4)/(3)`
`=7.47 KM"/"sec`.


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