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If ey(x + 1) = 1, show that d2y/dx2 = (dy/dx)2 |
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Answer» Given that ey(x + 1) = 1 ⇒ ey = 1/(x + 1) Differentiating both sides w.r.t. x, we get ey(dy/dx) = - 1/(x + 1)2 ⇒ 1/(x + 1)dy/dx = - 1/(x + 1)2 ⇒ dy/dx = - 1/(x + 1) Again, Differentiating both sides w.r.t. x, we get d2y/dx2 = 1/(x + 1)2 = (- 1/(x + 1))2 = (dy/dx)2 |
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