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If f(x) = \( \begin{cases}x + \lambda ; & x < 3\\4;& x = 3\\3x - 5; & x > 3\end{cases}\) is continuous at x = 3 then the value of λ will be :(a) 4(b) 3(c) 2(d) 1 |
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Answer» Answer is (d) Left hand limit f (3 – 0) = limh→0 f (3 – h) = limh→0 (3 – h) + λ = (3 – 0) + λ = 3 + λ ∵ At x = 3, function is continuous then f (3 – 0) = f (3) 3 + λ = 4 ⇒ λ = 4 – 3 λ = 1 |
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