1.

If f(x) = \( \begin{cases}x + \lambda ; & x < 3\\4;& x = 3\\3x - 5; & x > 3\end{cases}\) is continuous at x = 3 then the value of λ will be :(a) 4(b) 3(c) 2(d) 1

Answer»

Answer is (d)

Left hand limit

f (3 – 0) = limh→0 f (3 – h)

= limh→0 (3 – h) + λ

= (3 – 0) + λ

= 3 + λ

∵ At x = 3, function is continuous then

f (3 – 0) = f (3)

3 + λ = 4

⇒ λ = 4 – 3

λ = 1



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