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If `f(x)=[x](sin kx)^(p)` is continuous for real x, then (where [.] represents the greatest integer function)A. `k in [npi, n in I], p gt 0`B. `k in {2npi, n in I}, p gt0`C. `k in {npi, n in I}, p in R-{0}`D. `k in {npi, n I, n ne 0}, p in R-{0}` |
Answer» Correct Answer - A `f(x)=[x](sin kx)^(p)` `(sin kx)^(p)` is continuous function `AA x in R, k in R` and `p gt0.[x]` is discontinuous at `x in I` For `k=npi, n in I` `f(x)=[x](sin(n pix))^(p)` `underset(xrarra)(lim)f(x)=0, a in I` and f(a) = 0 So, f(x) becomes continuous for all `x in R` |
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