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If five equal pieces of a resistance wire having 5 Omega resistance are connected in parallel, their equivalent resistance will be …………… .

Answer»

`1/5 Omega`
`1 Omega`
`5Omega`
`25 Omega`

Solution :When a resistance WIRE having `5 Omega` resistance is cut into five equal pieces, each piece will have resistance `1 Omega`,i.e., `R_1 = R_2 = R_3 = R_4 =R_5 =1 Omega`.
The equivalent resistance (`R_p`) of their PARALLEL combination is given by,
`1/R_p = 1/R_1 + 1/R_2 + 1/R_3 + 1/R_4 + 1/R_5`
`:. 1/R_p = 1/1+ 1/1 + 1/1 + 1/1 + 1/1`
`:. 1/R_p = 5/1`
`:. R_p = 1/5 Omega`


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