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If half-life of a substance is `3.8` days and its quantity is `10.38 gm`. Then substance quantity remaining left after `19` days will beA. `0.151 gm`B. `0.32 gm`C. `1.51 gm`D. `0.16 gm` |
Answer» Correct Answer - B (b) Number of half-lives `n = (19)/(3.8) = 5`, Now `(N)/(N_0) = ((1)/(2))^n` `rArr (N)/(10.38) = ((1)/(2))^5 rArr N = 10.38 xx ((1)/(2))^5 = 0.32 gm`. |
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