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If in ` A B C ,A C`is double of `A B`, then the value of `cot(A/2)cot((B-C)/2)`is equal to`1/3`(b) `-1/3`(c) `3`(d) `1/2` |
Answer» b=2c-(1) `tan((B-C)/2)=(b-c)/(b+c)cot(A/2)` `cot(A/2)cot((B-C)/2)=(b+c)/(b-c)=(2c+c)/(2c-c)=3`. |
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