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If in the hydrogen atom P.E. At `oo` is chosen to be 13.6 eV then the ratio of T.E. to K.E.. For `1^(st)` orbit of H-atom is |
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Answer» Correct Answer - A `T.E=-13.6-13.6=0` `K.E.=13.6+13.6=27.2` `(TE)/(KE)=0` |
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