1.

If ionising energy of H atom is 13.6 eV, then the second ionising energy of He should beA. 27.2 eVB. 40.8 eVC. 54.4 eVD. 108.8 eV

Answer» Correct Answer - C
`E_H=(-13.6)/n^2 , (E_1)_H=-13.6 eV`
`(E_1)He^(+)=-13.6Z^2/n^2=-13.6xx2^2/1=-54.4` eV
The second I.E. =`E_oo-(E_1)_(He^+)`
`=0-(-54.4) eV=54.4 eV`


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