1.

If K_(c)for the formation of HI from H_(2) and I_(2) each is 64, then calculate K_(c) for the decomposition of 1 mole of HI.

Answer»

Solution :`H_(2) + I_(2) hArr 2HI`
`1//2H_(2)+ 1//2 I_(2) hArr HI`
`IMPLIES K_(c_(1))=([HI]^(2))/([H_(2)]^(1)[I_(2)]^(1)) implies K_(c_(2))=([HI])/([H_(2)]^(1//2)[I_(2)]^(1//2))`
`therefore K_(c_(2))=(1)/(sqrt(K_(c_(1))))=(1)/(sqrt(64))=(1)/(8)=0.125`


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