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If `lambda_(1)` and `lambda_(2)` denote the de-Broglie wavelength of two particles with same masses but charges in the ratio of `1:2` after they are accelerated from rest through the same potential difference, thenA. `lambda_(1) = lambda_(2)`B. `lambda_(1) lt lambda_(2)`C. `lambda_(1) gt lambda_(2)`D. `lambda_(1) lt sqrt(lambda_(2))` |
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Answer» Correct Answer - C `lambda = (h)/(sqrt(2.m.q.v))` |
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