InterviewSolution
Saved Bookmarks
| 1. |
If `lamda_o and lamda` be the threshold wavelength and wavelength of incident light , the velocity of photoelectron ejected from the metal surface is :A. `sqrt((2h)/(m)(lamda_(0)-lamda)`B. `sqrt((2hc)/(m)(lamda_(0)-lamda))`C. `sqrt((2hc)/(m)((lamda_(0)-lamda)/(lamdalamda_(0))))`D. `sqrt((2h)/(m)((1)/(lamda_(0))-(1)/(lamda)))` |
|
Answer» Correct Answer - C Absorbed energy=Threshold energy+kinetic energy of photoelectrons `(hc)/(lamda)=(hc)/(lamda_(0))+(1)/(2)mv^(2)` `v=sqrt((2hc)/(m)((lamda_(0)-lamda))/(lamdalamda_(0)))`. |
|