1.

If `lamda_o and lamda` be the threshold wavelength and wavelength of incident light , the velocity of photoelectron ejected from the metal surface is :A. `sqrt((2h)/(m)(lamda_(0)-lamda)`B. `sqrt((2hc)/(m)(lamda_(0)-lamda))`C. `sqrt((2hc)/(m)((lamda_(0)-lamda)/(lamdalamda_(0))))`D. `sqrt((2h)/(m)((1)/(lamda_(0))-(1)/(lamda)))`

Answer» Correct Answer - C
Absorbed energy=Threshold energy+kinetic energy of photoelectrons
`(hc)/(lamda)=(hc)/(lamda_(0))+(1)/(2)mv^(2)`
`v=sqrt((2hc)/(m)((lamda_(0)-lamda))/(lamdalamda_(0)))`.


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