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If latent heat of fusion of ice is 80 cals per g at `0^(@),` calculate molal depression constant for water.A. 18.36B. 186.3C. 1.863D. 0.1863

Answer» Correct Answer - C
`"K"_("f")=("RT"_("f")^(2))/(1000l_("f"))" Here R"=2"cals","T"_("f")=0+273=273"K, "l_("f")=80"cals"`
`"K"_("f")=(2xx273xx273)/(1000xx80)=1.863`


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