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If `log_(3) .(x^(3))/(3) - 2 log_(3) 3x^(3)=a-b log_(3)x`, then find the value of a + b.A. 6B. -6C. 0D. -3 |
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Answer» Correct Answer - C Use log a - log b = `log.(a)/(b)` and log a + log b = log ab. |
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