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If `"log"_(3) x + "log"_(9)x^(2) + "log"_(27)x^(3) = 9`, then x =A. 3B. 9C. 27D. none of these |
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Answer» Correct Answer - C We have, `"log"_(3)x + "log"_(9)x^(2) + "log"_(27)x^(3) = 9` `rArr "log"_(3) x + "log"_(3^(2)) x^(2) + "log"_(3^(3)) x^(3) = 9` `rArr "log"_(3) x + (2)/(2) "log"_(3) x + (3)/(3) "log"_(3)x =9` `rArr 3 "log"_(3) x = 9 rArr "log"_(3) x = 3 rArr x = 3^(3)=27` |
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