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If log 5 = 0.699 and `(1000)^(x)` = 5, then find the value of x.A. 0.0699B. 0.0233C. 0.0233D. 10 |
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Answer» Correct Answer - C Taking logarithms for `10^(3x)=5` and substituting in the given equation we get the value of x. |
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