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If `log_(6)x + 2log_(36)x + 3log_(216)x = 9` then x = ______A. 6B. 36C. 216D. None of these |
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Answer» Correct Answer - C `log_(6)x+ 2log_(36) + 3log_(216)x = 19` ` Rightarrow log_(6)x + log_(6)x + log_(6)x =9` ` Rightarrow 3 log_(6)x = 9 Rightarrow log_(6)x = 3` ` Rightarrow x= 6^(3)` ` thereforex= 216` |
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