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If `("log"_(a)x)/("log"_(ab)x) = 4 + k + "log"_(a)b, "then" k=` |
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Answer» Correct Answer - D We have, `("log"_(a)x)/("log"_(ab)x) = ("log"_(x)ab)/("log"_(x)a) = "log"_(a)ab = "log"_(a)a + "log"_(a)b = 1 + "log"_(a)b` `therefore ("log"_(a)x)/("log"_(ab)x) = 4 + k + "log"_(a)b` `rArr 1 + "log"_(a)b = 4 + k + "log"_(a)b rArr 1 = 4 + k rArr k = -3` |
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