1.

If `(log)_k xdot(log)_5k=(log)_x5,k!=1,k >0,`then `x`is equal to`k`(b) 1/5(c) 5 (d) none of these

Answer» `log_y^x=log_c^x/log_c^y`
`(logx/logk)*(logk/log5)=log5/logx`
`(logx)^2=(log5)^2`
`logx=log5`
`x=5`.


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