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If ` log_(2) x xx log_(3) x = log_(2) x + log_(3) x`, then find x . |
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Answer» Correct Answer - x = 1, 6 ` log_(2) x xx log_(3) x = log_(2) x + log_(3) x` ` rArr (log x)/(log 2) *(log x)/(log 3) =(log x)/(log 2) +(log x)/(log 3) ` ` rArr log x = 0` ` or (log x)/(log 2*log 3) = 1/(log 2) + 1/(log 3) ` ` rArr x = 1 or log x = log 2+ log 3` `rArr x = 1 or log x = log 6` ` rArr x = 1 or x = 6` |
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