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Let `a= log_(3) 20, b = log_(4) 15 and c = log_(5) 12`. Then find the value of `1/(a+1)+1/(b+1)+1/(c+1)`. |
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Answer» We have `a+1 = log_(3) 20 + log_(3) 3 = log_(3) 60` ` b+ 1 = log_(4) 15 + log_(4) 4 = log_(4) 60` ` c+1 = log_(5) 12+ log_(5) 5 = log_(5) 60` `1/(a+1)+1/(b+1)+1/(c+1)=1/(log_(3) 60)+1/(log_(4)60)+1/(log_(5)60)` ` =log_(60)3+log_(60)4+log_(60)5` ` = log_(60)(3 xx 4 xx 5)` ` = log_(60) 60` ` = 1` |
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