1.

If log10√(1 + x) + 3log10√(1 - x) = log10√(1 - x2) + 2. Find x.

Answer»

log10(x + 1)1/2 + log10(1 – x)3/2 = log10(1 – x2)1/2 + log10010 

⇒ (x + 1)1/2(1 – x)3/2 = (1 – x2)1/2 – 100 

⇒ √(1 - x2) (1 – x – 100) = 0 ⇒ x = ±1. x = -99 

But x ≠ ± 1, -99 

∴ There is no value of x exists.



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