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If log10√(1 + x) + 3log10√(1 - x) = log10√(1 - x2) + 2. Find x. |
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Answer» log10(x + 1)1/2 + log10(1 – x)3/2 = log10(1 – x2)1/2 + log10010 ⇒ (x + 1)1/2(1 – x)3/2 = (1 – x2)1/2 – 100 ⇒ √(1 - x2) (1 – x – 100) = 0 ⇒ x = ±1. x = -99 But x ≠ ± 1, -99 ∴ There is no value of x exists. |
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