1.

If log3 [log2 (log3x)] = 1, show that x = 6561.

Answer»

log3 [log2(log3 x)] = 1

\(\therefore\) log2 (log3 x) = 31

\(\therefore\) log3 x = 23

\(\therefore\) log3 x = 8

\(\therefore\) x = 38

\(\therefore\) x = 6561



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