1.

If m is the mid-point and l is the upper limit of a class in a continous frequency distribution, then lower class limit of the class isA. 2m-uB. 2m+uC. m-uD. m+u

Answer» Correct Answer - A
Let l be the lower limit. Then,
`m=(l+u)/(2)Rightarrow l=2m-u`


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