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The mid value of a class interval in 42 and the class size is 10 then find lower and upper limits.A. 37-47B. 37.5-47.5C. 36.5-47.5D. 36.5-46.5

Answer» Correct Answer - A
Let the lower limit be x. Then upper limit=(x+10).
`therefore (x(x+10))/(2)=42 Rightarrow 2x+10=84 Rightarrow 2x=84 Rightarrow x=37`
`therefore` lower limit=37 and upper limit=47


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