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The mid value of a class interval in 42 and the class size is 10 then find lower and upper limits.A. 37-47B. 37.5-47.5C. 36.5-47.5D. 36.5-46.5 |
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Answer» Correct Answer - A Let the lower limit be x. Then upper limit=(x+10). `therefore (x(x+10))/(2)=42 Rightarrow 2x+10=84 Rightarrow 2x=84 Rightarrow x=37` `therefore` lower limit=37 and upper limit=47 |
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