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In a frequency distribution, the mid values of a class is 10 and width of the class is 6. The lower limit of the class isA. 6B. 7C. 8D. 12 |
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Answer» Correct Answer - B Let the lower limit be a. Then, upper limit=a+3. Mid value of `=(a+a+6)/(2)=(2a+6)/(2)=a+3` `therefore a+3=10 Rightarrow a=7` `therefore` lower limit of the class is 7. |
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