1.

If momentum (p), area (A) and time(t) are taken to be fundamental quantities then energy has the dimensional formula

Answer»

`[PA^(1//2)T^(-1)]`
`[pA^(-1//2)T^(1)]`
`[p^(2)AT]`
`[pA^(-1)T]`

Solution :Energy = Force `×` Length
`=("CHANGE in momentum")/("TIME")xxsqrt("area")=[pA^(1//2)A^(-1)]`


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