If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year isA. `N_0//8`B. `N_0//16`C. `N_0//2`D. `N_0//4`

If `N_(0)` is the original mass of the substance of half - life period

1.	If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year isA. `N_0//8`B. `N_0//16`C. `N_0//2`D. `N_0//4`
Answer» Correct Answer - A (a) `N = N_0 ((1)/(2))^((t)/(T_1//2)) = N_0 ((1)/(2))^((15)/(5)) = (N_0)/(8)`.

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If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year isA. `N_0//8`B. `N_0//16`C. `N_0//2`D. `N_0//4`

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