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If `overset(a)underset(0)int(1)/(1+4x^(2))dx=(pi)/(8)`, then a equalsA. `(1)/(4)`B. `-(1)/(2)`C. `(3)/(2)`D. `(1)/(2)` |
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Answer» Correct Answer - D Given , ` int _(0)^(p) (dx)/(1+4x^(2))= pi/8` , ` LHS = int _(0)^(p) (dx)/(1+4x^(2)) = 1/4 int _(0)^(p) (dx)/(1/4+x^(2)) = 1/4 xx (1)/(1/2) [ tan^(-1)(x/(1/2))]_(0)^(p)` ` rArr 1/2 (tan^(-1) 2p ) = pi/8` ` rArr tan^(-1) 2p = pi/4 rArr 2p = 1` ` rArr p = 1/2` |
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