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If p times pth is same as q times qth term and first term is Pq, then find the sum of (p+q)terms.

Answer» p[a+(p−1)a]=q[a+(q−1)d]ora(p−q)+(p2−q2)d+(q−p)d=0ora(p−a)+(p+a)(p−q)−(p−q)d=0ora+(p+q−1)d=0This is the\xa0(p+q)\xa0th term.


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